Electrical Machines · Induction Motors

Induction Motor Mastery: Starting, Running, & Max Torquee

Dr. Mithun Mondal BITS Pilani, Hyderabad Campus Electrical Machines

Demonstrative Video

SECTION 01

Starting Torque

  • The torque developed by the motor at the instant of starting is called starting torque

  • In some cases, it is greater than the normal running torque, whereas other cases it is somewhat less

\[\begin{aligned} E_{2} & =\mbox{rotor e.m.f per phase} ~{\color{magenta}{\text{at standstill}}}\\ R_{2} & =\mbox{rotor resistance/phase}\\ X_{2} & =\mbox{rotor reactance/phase} ~{\color{magenta}{\text{at standstill}}}\\ \therefore Z_{2} & =\sqrt{\left(R_{2}^{2}+X_{2}^{2}\right)}=\mbox{rotor impedance/phase } ~{\color{magenta}{\text{at standstill}}}\\ \Rightarrow I_{2} & =\dfrac{E_{2}}{Z_{2}}=\dfrac{E_{2}}{\sqrt{\left(R_{2}^{2}+X_{2}^{2}\right)}}\\ \Rightarrow\cos\phi_{2} & =\dfrac{R_{2}}{Z_{2}}=\dfrac{R_{2}}{\sqrt{\left(R_{2}^{2}+X_{2}^{2}\right)}} \end{aligned}\]
Key Concepts
  • \[\begin{aligned} T_{st} & =K_{1}E_{2}\cdot\dfrac{E_{2}}{\sqrt{\left(R_{2}^{2}+X_{2}^{2}\right)}}\times\dfrac{R_{2}}{\sqrt{\left(R_{2}^{2}+X_{2}^{2}\right)}}\\ \Rightarrow T_{st} & =\dfrac{K_{1}E_{2}^{2}R_{2}}{\left(R_{2}^{2}+X_{2}^{2}\right)} \end{aligned}\]
    Standstill or starting torque
  • \[\therefore T_{st} = K_2 \cdot \dfrac{R_2}{\left(R_2^2+X_2^2\right)} = K_2 \dfrac{R_2}{Z_2^2}\]
    both are constant and hence is constant, then If
  • \[T_{st}=\dfrac{3}{2\pi N_{s}}\cdot\dfrac{E_{2}^{2}R_{2}}{R_{2}^{2}+X_{2}^{2}}\]
    Now,\(K_1=\dfrac{3}{2\pi N_s}\)synchronous speed in r.p.s where,
SECTION 02

Starting torque of a squirrel-cage motor

  • The resistance of the Squirrel-cage motor is fixed and small as compared to its reactance which is very large especially at the start because at standstill the frequency of the rotor currents equal the supply frequency

  • Hnece, the strating current \(I_2\) of the rotor though very large in magnitude, lags by a very large angle behind \(E_2\), with the result that the starting torque per ampere is very poor

  • It is roughly 1.5 times the full-load torque although the starting current is 5 to 7 times the full-load current

  • Hence such motors are not ver useful where the motor has to start against heavy loads

SECTION 03

Starting torque of a slip-ring motor

  • The starting torque of such motor is increased by improving its power factor by adding external resistance in the rotor circuit from the star-connected rheostat

  • The rheostat resistance being progressively cut out as the motor gathers speed

  • Addition of external resistance, increase the rotor impedance and so reduce the rotor current

  • At first the effect of improved power factor predominates the current - decreasing effect of impedance. Hence, the starting torque is increased

  • But after a certain point, the effect of increased impedance predominates the effect of improved power factor and so the torque starts decreasing

SECTION 04

Condition for maximum Starting torque

\[\begin{aligned} T_{st} & =\dfrac{K_{2}R_{2}}{R_{2}^{2}+X_{2}^{2}}\\ \therefore\dfrac{dT_{st}}{dR_{2}} & =K_{2}\left[\dfrac{1}{R_{2}^{2}+X_{2}^{2}}-\dfrac{R_{2}\left(2R_{2}\right)}{\left(R_{2}^{2}+X_{2}^{2}\right)^{2}}\right]=0\\ & \Rightarrow R_{2}^{2}+X_{2}^{2}=2R_{2}^{2}\\ \Longrightarrow & R_{2}=X_{2} \end{aligned}\]
  • Thus, \(T_{st}\) is maximum when \(R_2=X_2\)

SECTION 05

Effect of change in supply voltage on Starting torque

\[\begin{aligned} E_{2} & \propto V\\ \therefore T_{st} & =\dfrac{K_{1}E_{2}^{2}R_{2}}{R_{2}^{2}+X_{2}^{2}}=\dfrac{K_{1}V^{2}R_{2}}{R_{2}^{2}+X_{2}^{2}}=\dfrac{K_{3}V^{2}R_{2}}{Z_{2}^{2}}\\ \Longrightarrow T_{st} & \propto V^{2} \end{aligned}\]
  • Thus, torque is very sensitive to change in supply voltage

  • A change in 5% in \(V\) will produce a change of approx. 10% in the rotor torque

SECTION 06

Rotor E.M.F and Reactance under Running Conditions

  • At standstill, \(s=1\) and \(f_r=f\)

  • \(E_2\) at standstill is maximum because relative speed between the rotor and the revolving stator flux is maximum

  • In fact, IM is equivalent to 3-phase TF with short-circuited rotating secondary

  • Under running condition, the relative speed decreases, \(E_2 \propto\) relative speed also decreases

Due to decrease in the frequency of,also decreases
  • \[\begin{aligned} E_r & = sE_2\\ f_r & = sf_2\\ X_r & = sX_2 \end{aligned}\]
    \(f_2\)\(E_2, X_2,\)Hence under running condition
  • Due to decrease in the frequency of \(E_2\), \(X_r\) also decreases

SECTION 07

Torque Under Running Conditions

\[\begin{aligned} T_{r} & \propto\phi I_{r}\cos\phi_{2}\\ \Rightarrow T_{r} & \propto E_{2}\dfrac{E_{r}}{Z_{r}}\cdot\dfrac{R_{2}}{Z_{r}}~\left(\because E_{2}\propto\phi\right)\\ \Rightarrow T_{r} & \propto\left(E_{2}\right)\left(\dfrac{sE_{2}}{\sqrt{R_{2}^{2}+\left(sX_{2}\right)^{2}}}\right)\left(\dfrac{R_{2}}{\sqrt{R_{2}^{2}+\left(sX_{2}\right)^{2}}}\right)\\ \Rightarrow T_{r} & \propto\dfrac{sE_{2}^{2}R_{2}}{R_{2}^{2}+\left(sX_{2}\right)^{2}}\\ \Rightarrow T_{r} & =\dfrac{3}{2\pi N_{s}}\left[\dfrac{sE_{2}^{2}R_{2}}{R_{2}^{2}+\left(sX_{2}\right)^{2}}\right] \\ & \Rightarrow \text{Substitute}~ s=1~\text{ to get}~ T_{st} \end{aligned}\]
SECTION 08

Condition for maximum torque under running condition

  • \[T_r = K_1 \cdot \dfrac{sE_2^2R_2}{R_2^2+(sX_2)^2}\]
    The torque under running condition is given by
  • To make calculation simple take \(Y=1/T_r\)

Key Concepts
  • \[\begin{aligned} \dfrac{dY}{ds} & =\dfrac{d}{ds}\left[\dfrac{R_{2}^{2}+\left(sX_{2}\right)^{2}}{K_{1}sE_{2}^{2}R_{2}}\right]\\ &=\dfrac{d}{ds}\left[\dfrac{R_{2}}{K_{1}sE_{2}^{2}}+\dfrac{sX_{2}^{2}}{K_{1}E_{2}^{2}R_{2}}\right]\\ \Rightarrow\dfrac{dY}{ds} & =\dfrac{-R_{2}}{K_{1}s^{2}E_{2}^{2}}+\dfrac{X_{2}^{2}}{K_{1}E_{2}^{2}R_{2}}=0\\ \Rightarrow\dfrac{R_{2}}{K_{1}s^{2}E_{2}^{2}} & =\dfrac{X_{2}^{2}}{K_{1}E_{2}^{2}R_{2}}\\ \Longrightarrow R_{2} & =sX_{2} \end{aligned}\]
    Then, to obtain the condition of maximum torque
Key Concepts
  • \[\begin{aligned} T_{max} & =K_{1}\dfrac{sE_{2}^{2}\left(sX_{2}\right)}{\left(sX_{2}\right)^{2}+\left(sX_{2}\right)^{2}}\\ & =K_{1}\dfrac{sE_{2}^{2}\left(sX_{2}\right)}{2\left(sX_{2}\right)^{2}}\\ & =K_{1}\dfrac{E_{2}^{2}}{2X_{2}}\\ \Rightarrow T_{max} & =\dfrac{3}{2\pi N_{s}}\cdot\dfrac{E_{2}^{2}}{2X_{2}} \end{aligned}\]
    , and thus the maximum torque is Thus, torque under running condition is maximum when
is independent of the
  • \(T_{max}\) is independent of the \(R_2\)

  • However, the speed or slip at which \(T_{max}\) occurs is determined by \(R_2\)

  • By varying \(R_2\) (possible only with slip-ring motors) \(T_{max}\) can be made to occur at any desired slip (or motor speed)

  • \(T_{max} \propto 1/X_2\) Hence, it should be kept as small as possible

  • \(T_{max} \propto V^2\)

  • For obtaining \(T_{max}\) at starting (\(s=1\)), \(R_2=X_2\)

SECTION 09

Rotor Torque and Breakdown Torque

\[T=T_{b}\left[\dfrac{2}{\left(s_{b}/s\right)+\left(s/s_{b}\right)}\right]\]
\(s_b\) by the following equation can be expressed in terms of the maximum (or breakdown) torque The rotor torque at any slip