Solved Problems on Kirchhoff's Voltage and Current Laws (KVL & KCL)

Demonstrative Video


Problem-1

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Solution-1


Problem-2

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Solution-2

  • Applying KVL in Loop-2 3VR5I4VR=02VR=5I+4


Problem-3

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Solution-3

  • KVL in first loop gives 5=2I1I1=2.5 A

  • Va=I1=2.5 V


Problem-4

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Solution-4

  • KVL in first loop gives 8+12VR2=0VR2=4 V

  • Also applying KVL VR27+9vx=0vx=6 V


Problem-5

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Solution-5

1=i23+7i2=3 A


Problem-6

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Solution-6

Problem-7

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Solution-7

Problem-8

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Solution-8

Problem-9

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Solution-9

Problem-10

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Solution-10